Rubidium Has How Many Valence Electrons?

One valence electron, which is situated in the s-orbital of the atom’s fifth energy level, is present in rubidium. A total of 37 electrons make up rubidium, as shown by the element’s electron configuration, which is 1s2 2s2p6 3s2p6d10 4s2p6 5s1.

Rubidium is represented by the chemical symbol Rb on the periodic table of elements. It is a member of the family of elements known as alkali metals and has the atomic number 37. Ionic radius of a rubidium atom is 1.52 angstroms, and atomic radius is 2.98 angstroms. Rubidium contains 48 neutrons in its most common state and a charge of +1 in an ionic state.

Misha Khatri
Misha Khatri is an emeritus professor in the University of Notre Dame's Department of Chemistry and Biochemistry. He graduated from Northern Illinois University with a BSc in Chemistry and Mathematics and a PhD in Physical Analytical Chemistry from the University of Utah.

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