What is the mass of (NH4)3 PO4 in grammes?

(NH4)3PO4 has a molar mass of 149.087 grammes per mole. The number of atoms in each element in the molecular formula for this molecule, as well as their atomic weights, are used to arrive at this answer.

Each element has three atoms of nitrogen, twelve atoms of hydrogen, one atom of phosphorus, and four atoms of oxygen, according to the chemical formula (NH4)3PO4.

According to the periodic table, nitrogen has an atomic mass of 14.0067 grammes per mole, hydrogen has an atomic mass of 1.00794, phosphorus has an atomic mass of 30.973761, and oxygen has an atomic mass of 15.9994.

To calculate the mass of the compound, ammonium phosphate, multiply the number of atoms in each element by their atomic mass, then add the results: [(14.0067 grams/mol x 3) + (1.00794 grams/mol x 12) + (30.973761 grams/mol x 1) + (15.9994 grams/mol x 4)], which equals 149.087 grammes per mole when rounded to the nearest thousandth.

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Misha Khatri
Misha Khatri is an emeritus professor in the University of Notre Dame's Department of Chemistry and Biochemistry. He graduated from Northern Illinois University with a BSc in Chemistry and Mathematics and a PhD in Physical Analytical Chemistry from the University of Utah.


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